How to get a value or a part from url?

Question

I have a URL as follows http://localhost:8080/list/PEPPR_BDCAREUGWJ

I need "PEPPR_BDCAREUGWJ" from this url. How to do this by javascript?

Possible duplicate of [Last segment of URL](https://stackoverflow.com/questions/4758103/last-segment-of-url) — Remco Bravenboer, Apr 21 '19 at 15:00
Possible duplicate of [How do I parse a URL into hostname and path in javascript?](https://stackoverflow.com/questions/736513/how-do-i-parse-a-url-into-hostname-and-path-in-javascript) — weegee, Apr 21 '19 at 15:12

Maheer Ali · Accepted Answer · 2019-04-21T15:15:13.430

1

You can use split() and get the last value from array.

let str = 'http://localhost:8080/list/PEPPR_BDCAREUGWJ'
let res = str.split('/').pop()

console.log(res)

Another way can be using lastIndexOf() and slice()

let str = 'http://localhost:8080/list/PEPPR_BDCAREUGWJ'
let res = str.slice(str.lastIndexOf('/')+1)

console.log(res)

You can also use regular expression.

let str = 'http://localhost:8080/list/PEPPR_BDCAREUGWJ'
let res = /\/[^\/]+$/.exec(str)[0].slice(1)

console.log(res)

edited Apr 21 '19 at 15:15

answered Apr 21 '19 at 14:58

Maheer Ali

the first solution that you give, I think it should be `res[res.length -1]` or `res.pop()` – YouneL Apr 21 '19 at 15:14

score 1 · Answer 2 · answered Apr 21 '19 at 14:59

1

Just split by slash(/) using String#split method and get last part from the array using Array#pop method.

let str = 'http://localhost:8080/list/PEPPR_BDCAREUGWJ'
let res = str.split('/').pop();

console.log(res)

answered Apr 21 '19 at 14:59

Pranav C Balan

2 Answers2