How can I declare a struct array with the size 2^18

Question

This is my struct

struct Entry {
    int a;
    int b;
};

int main() {

    struct Entry data[260000]; //ok
    struct Entry data[262144]; //crash

    return 0;
}

I want to declare an array of Entry with the size is 2^18 (262144 elements) But I'm not able to do so. It seems like I go beyond the max. Is there another way to do this?

@Jasen it crashed on Windows 10 64bit. I'm not sure it is related to OS or IDE or something else though. — Louis Tran, May 07 '19 at 02:12

score 4 · Accepted Answer · answered May 07 '19 at 02:07

4

There is not ehough room in the auto context (on the stack) for that array, declare it static or as a global, or allocate it dynamically.

answered May 07 '19 at 02:07

Jasen

11,837
2
30
48

1

Perfect! Thanks. – Louis Tran May 07 '19 at 02:11
2

... or increase the stacksize. linker options. – Swordfish May 07 '19 at 03:03

How can I declare a struct array with the size 2^18

1 Answers1