String tranformation into Clean list of int

Question

I ideally want to turn this 100020630 into [100,020,630] but so far i can only do this "100.020.630" into ["100","020","630"]

def fulltotriple(x):
    X=x.split(".")
    return X

print(fulltotriple("192.123.010"))

for some additionnal info my goal is no turn ip adresses into bin adresses using this as a first step =)

edit: i have not found any way of getting the list WITHOUT the " " in the list on stack overflow

Possible duplicate of [Split string every nth character?](https://stackoverflow.com/questions/9475241/split-string-every-nth-character) — R4444, May 07 '19 at 14:37

score 4 · Answer 1 · answered May 07 '19 at 14:36

4

Here's one approach using a list comprehension:

s = '100020630'
[s[i:i + 3] for i in range(0, len(s), 3)]
# ['100', '020', '630']

answered May 07 '19 at 14:36

yatu

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there is still a problem the '' remain in the list – Profy May 08 '19 at 15:22
If you want them as integers, use `[int(s[i:i + 3]) for i in range(0, len(s), 3)]` @PablitoGnp – yatu May 08 '19 at 15:29

AdamGold · Answer 2 · 2019-05-29T09:34:17.987

You could use the built-in wrap function:

In [3]: s = "100020630"                                                                                                                                                                                          
In [4]: import textwrap                                                                                                                                                                                                                                                                                                                                                                                
In [6]: textwrap.wrap(s, 3)                                                                                                                                                                                       
Out[6]: ['100', '020', '630']

Wraps the single paragraph in text (a string) so every line is at most width characters long. Returns a list of output lines, without final newlines.

If you want a list of ints:

[int(num) for num in textwrap.wrap(s, 3)]

Outputs:

[100, 020, 630]

You can use a list comprehension to have a list of `int`s. Updated my answer. — AdamGold, May 29 '19 at 09:34

score 4 · Answer 3 · answered May 07 '19 at 14:46

If you want to handle IP addresses, you are doing it totally wrong.

IP address is a 24-binary digit number, not a 9-decimal digit. It is splitted for 4 sub-blocks, like: 192.168.0.1. BUT. In decimal view they all can be 3-digit, or 2-digit, or any else combination. I recommend you to use ipaddress standard module:

import ipaddress

a = '192.168.0.1'

ip = ipaddress.ip_address(a)
ip.packed

will return you the packed binary format:

b'\xc0\xa8\x00\x01'

If you want to convert your IPv4 to binary format, you can use this command:

''.join(bin(i)[2:] for i in ip.packed)

It will return you this string:

'110000001010100001'

thanks how do i put this in a list of 4 group of 8 number – Profy May 08 '19 at 15:23 — Profy, May 08 '19 at 15:23

Kunal Mukherjee · Answer 4 · 2019-05-09T05:25:36.983

3

Use regex to find all matches of triplets \d{3}

import re

str = "100020630"

def fulltotriple(x):
    pattern = re.compile(r"\d{3}")
    return [int(found_match) for found_match in pattern.findall(x)]


print(fulltotriple(str))

Outputting:

[100, 20, 630]

edited May 09 '19 at 05:25

answered May 07 '19 at 14:41

Kunal Mukherjee

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there is still a problem the '' remain in the list – Profy May 08 '19 at 15:23
@PablitoGnp I didnt get you sorry, care to explain – Kunal Mukherjee May 08 '19 at 15:48
i want [192] instead of ["192"] for it to be usable as an int =) – Profy May 08 '19 at 15:50

score 3 · Answer 5 · answered May 07 '19 at 15:36

3

You could use wrap which is a inbuilt function in python

from textwrap import wrap

def fulltotriple(x):
    x = wrap(x, 3)
    return x

print(fulltotriple("100020630"))

Outputs:

['100', '020', '630']

answered May 07 '19 at 15:36

Hass786123

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score 3 · Answer 6 · answered May 07 '19 at 15:57

3

You can use python built-ins for this:

text = '100020630'

# using wrap

from textwrap import wrap
wrap(text, 3)
>>> ['100', '020', '630']


# using map/zip

map(''.join, zip(*[iter(text)]*3))
>>> ['100', '020', '630']

answered May 07 '19 at 15:57

Mikey Lockwood

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there is still a problem the '' remain in the list – Profy May 08 '19 at 15:23
@PablitoGnp You can do [int(x) for x in wrap(text, 3)] or look at Yatu's answer – Mikey Lockwood May 08 '19 at 15:45

ncica · Accepted Answer · 2019-05-08T15:40:41.373

1

def fulltotriple(data):
    result = []
    for i in range(0, len(data), 3):
        result.append(int(data[i:i + 3]))
    return (result)


print(fulltotriple("192123010"))

output:

[192, 123, 10]

edited May 08 '19 at 15:40

answered May 07 '19 at 14:37

ncica

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there is still a problem the '' remain in the list – Profy May 08 '19 at 15:22
can you explain what you mean by that @PablitoGnp – ncica May 08 '19 at 15:29
i want [192] instead of ["192"] for it to be usable as an int =) – Profy May 08 '19 at 15:31

String tranformation into Clean list of int

7 Answers7