Get past 5 minutes in easier way , javascript

Question

I want array of past five minutes in hour:minute format like below , But is there any other smarter way to do it easily ?

     var today = new Date();
     today.setSeconds(0);
     var last1 = new Date(today.getTime() - (1000*60));

     hour = last1.getHours();
     min = last1.getMinutes();
     final1 = hour+":"+min;

     var last2 = new Date(today.getTime() - (1000*120));
     var last3 = new Date(today.getTime() - (1000*180));
     var last4 = new Date(today.getTime() - (1000*240));
     var last5 = new Date(today.getTime() - (1000*300));

     var arr = [final1,final2,..and so on];

[`Array.prototype.map`](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map) — Aadit M Shah, May 08 '19 at 03:41
@MaheerAli `final1` is there. Hence `final2`, etc. should be in the same format. — Aadit M Shah, May 08 '19 at 03:43
final 2 , 3 , 4 , 5 etc same logic , since it will increase length of the code , I ignored for easy understanding. — Gracie williams, May 08 '19 at 03:44
`[1, 2, 3, 4, 5].map(function(i) { return new Date(new Date().getTime() - (1000 * 60 * i)) })` — fqhv, May 08 '19 at 03:54

Tyler Roper · Accepted Answer · 2019-05-08T04:35:02.197

I'd start by creating a reusable subtractMinutes function.

You could then create a new array of 5 items and use that subtractMinutes on each. The first item would have 0 minutes subtracted, the second would have 1 minute subtracted, so-on and so-forth.

const subtractMinutes = (date,minutes) => new Date(date - minutes * 60000);

const getPastMinutes = (minutes, startDate = new Date()) => {
  return [...Array(minutes)].map((i,idx) => {
    let newDate = subtractMinutes(startDate,idx);
    let hour = newDate.getHours().toString().padStart(2,'0');
    let minute = newDate.getMinutes().toString().padStart(2,'0');
    return `${hour}:${minute}`;
  });
};

console.log( getPastMinutes(5) );

Get past 5 minutes in easier way , javascript

1 Answers1