Can anyone explain how this works [1,2][bool("")]?

Question

I have no idea how this code works and it returns an output of the first element in the list.

I have tried with different inputs since though I'm getting all the same output.

[1,2,3][bool("")]

`""` is falsy in Python; so `bool("")` evaluates to `False`. `False` when used as an integer is `0` (`True` being `1`); `aList[0]` will return the first element. — Amadan, May 14 '19 at 10:09
Related: [Is it Pythonic to use bools as ints?](https://stackoverflow.com/q/3174392/1639625) — tobias_k, May 14 '19 at 10:14

score 0 · Answer 1 · answered May 14 '19 at 10:11

0

Since bool("")==False. Also, False is 0. Therefore [1,2,3][bool("")] is same as [1,2,3][0] which return first element of list ultimately.

answered May 14 '19 at 10:11

Vineet Jain

score 0 · Answer 2 · answered May 14 '19 at 10:13

0

bool("")==0

This is because "" is regarded as false. This means your statement will be,

[1,2,3][0]

which returns the first element of the list. In this case

answered May 14 '19 at 10:13

Diaco

2 Answers2