How to Get Next multiplication Number using in math function

Question

I have one case like a=14 when the user enters 6 then it will be check as next largest number of the multiplication number.

if 6*2>14 so not working and then that 6*3>14 so it is working.

I have no idea what was the name of the math function.

@dome I need to next multiplication number using of math function — Harshit Trivedi, May 14 '19 at 13:22
do you mean *integer division*? `14 // 6 = 2`... meaning `6*2 <= 14` and `6*3 > 14`... — hiro protagonist, May 14 '19 at 13:29
@HarshitTrivedi are you saying if `b` is user entered value find smallest `n` such that `b*n > a` — mujjiga, May 14 '19 at 13:30
Next multiplication number of what? Please edit the question to make it clear what you are trying to say @HarshitTrivedi — Devesh Kumar Singh, May 14 '19 at 13:37
@DeveshKumarSingh I mens that next multiplication number of that number just like 6*3 18>14 like that — Harshit Trivedi, May 14 '19 at 13:42
Is the [modulo function %](https://stackoverflow.com/questions/4432208/what-is-the-result-of-in-python) the name of the math function you're looking for? — Richard K Yu, May 14 '19 at 13:46
@DeveshKumarSingh output is 18 and it is any math function for that? — Harshit Trivedi, May 14 '19 at 13:46
Sure, I think you can use `math.ceil` for it, check my answer below @HarshitTrivedi — Devesh Kumar Singh, May 14 '19 at 13:53

score 2 · Answer 1 · answered May 14 '19 at 13:52

I think you just want:

factor = ((a-1) // n + 1)

Where a is you number like 14 and n is the smaller number to be multiplied by the factor:

a = 15
n = 7
factor = ((a-1) // n + 1)
print("factor", factor)
# 3
print("multiplied:", n * ((a-1) // n + 1))
# 21

it's not clear from your question what happens with an exact match, but this will return the exact factor:

a = 14
n = 7
factor = ((a-1) // n + 1)
print("factor", factor)
# 2
print("multiplied:", n * ((a-1) // n + 1))
#4

Richard K Yu · Answer 2 · 2019-05-14T13:48:47.423

1

This is my guess on what is meant based on the other comments:

user_number= int(input("What is your number? "))

check_number=int(input("What is the number to check against. "))

factor = 1
print(check_number, factor*user_number)
while(check_number>(factor*user_number)):
    print(factor)
    print("Not working.")
    factor+=1

working_factor = check_number%user_number+1
print("using modulo: ", working_factor)
print("Working factor: ",factor)

Output:

edited May 14 '19 at 13:48

answered May 14 '19 at 13:35

Richard K Yu

2,152
3
8
21

Hello, Can you please give working factor related answer. – Harshit Trivedi May 14 '19 at 13:41
It is at the bottom, it says working factor: 3, the variable factor stores the value. – Richard K Yu May 14 '19 at 13:42

score 1 · Answer 3 · answered May 14 '19 at 13:45

1

import math
a = 14
b = 6
mutiple = math.floor(a/b)+1
value = mutiple*b

print (mutiple, value)

answered May 14 '19 at 13:45

mujjiga

16,186
2
33
51

score 1 · Accepted Answer · answered May 14 '19 at 13:52

You can use math.ceil to calculate the ceiling of number/multiplier and multiply with it multiplier to get your result

import math

def func(number, multiplier):
    return multiplier * math.ceil(number/multiplier)

The output will be

print(func(14,6))
#18
print(func(18,6))
#18
print(func(19,6))
#24

Example for number=14 and multiplier=6, math.ceil(14/6) gives 3, and 6*3 gives 18

How to Get Next multiplication Number using in math function

4 Answers4