An external organization that I work with has given me access to a private (auth token protected) docker registry, and eventually I would like to be able to query this registry, using docker's HTTP API V2, in order to obtain a list of all the repositories and/or images available in the registry.
But before I do that, I'd first like to get some basic practice with constructing these types of API queries on a public registry such as Docker Hub. So I've gone ahead and registered myself with a username and password on Docker Hub, and also consulted the API V2 documentation, which states that one may request an API version check as:
GET /v2/
or request a list of repositories as:
GET /v2/_catalog
Using curl, together with the username and password that I used in order to register my Docker Hub account, I attempt to construct a GET request at the command line:
stachyra> curl -u stachyra:<my_password> -X GET https://index.docker.io/v2/
{"errors":[{"code":"UNAUTHORIZED","message":"authentication required","detail":null}]}
stachyra> curl -u stachyra:<my_password> -X GET https://index.docker.io/v2/_catalog
{"errors":[{"code":"UNAUTHORIZED","message":"authentication required","detail":[{"Type":"registry","Class":"","Name":"catalog","Action":"*"}]}]}
where of course, in place of <my_password>, I substituted my actual account password.
The response that I had been expecting from this query was a giant json message, listing thousands of repository names, but instead it appears that the API is rejecting my Docker Hub credentials.
Question 1: Do I even have the correct URL (index.docker.io) for the docker hub registry? (I made this assumption in the first place based upon the status information returned by the command line tool docker info, so I have good reason to think it's correct.)
Question 2: Assuming I have the correct URL for the registry service itself, why does my query return an "UNAUTHORIZED" error code? My account credentials work just fine when I attempt to login via the web at hub.docker.com, so what's the difference between the two cases?