Get result of array elements which are not matched into a single array

Question

I am new to Javascript. I have the following Mongodb Result Array

Result = [
          {
            "userId": "5cecfab4219aca350421b063",
            "providers": [
              "1689736266",
              "1598763690",
              "1528069614",
              "1831364272",
              "1548463045",
              "1245301159",
              "1386616399",
              "1790775971",
              "1629462130",
              "1992169783"
            ],
            "countByType": {
              "doctors": 6,
              "labs": 0,
              "hospitals": 0,
              "imagingCenters": 0,
              "other": 4
            },
            "id": "5cecfab4219aca350421b066"
          }
         ]

I have another Array

newArray = [1689736266, 1831364272, 123456789, 235695654 ];

how to get the array value in newArray which are not in MongoDBResult providers Array.

Eg: anotherArray = [123456789, 235695654];

Also how can I get the providers Array result using Javascript.

You can use array difference, refer https://stackoverflow.com/questions/1187518/how-to-get-the-difference-between-two-arrays-in-javascript — Dinesh Kumar DJ, May 29 '19 at 07:04
`Result.providers.filter(provider => !newArray.includes(provider))` — nick zoum, May 29 '19 at 07:05
@nickzoum you have to apply the filter on newArray not on providers, but this is the idea — PopHip, May 29 '19 at 07:07

score 1 · Accepted Answer · answered May 29 '19 at 07:06

1

You can use filter() on the newArray and check if its present in providers array of Result using includes()

const Result = [ { "userId": "5cecfab4219aca350421b063", "providers": [ "1689736266", "1598763690", "1528069614", "1831364272", "1548463045", "1245301159", "1386616399", "1790775971", "1629462130", "1992169783" ], "countByType": { "doctors": 6, "labs": 0, "hospitals": 0, "imagingCenters": 0, "other": 4 }, "id": "5cecfab4219aca350421b066" } ]
         
const newArray = [1689736266, 1831364272, 123456789, 235695654 ];
const anotherArray = newArray.filter(x => !Result[0].providers.includes(String(x)))

console.log(anotherArray)

answered May 29 '19 at 07:06

Maheer Ali

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Also how to check if anotherArray has some value inside if condition, only if, then execute this block. – Vishnu May 29 '19 at 07:17
@Vishnu `if(anotherArray.includes(some value)){...}` – Maheer Ali May 29 '19 at 07:22
Now I have empty array. So donot execute code if array is empty. How to achive this brother? – Vishnu May 29 '19 at 07:25
@Vishnu Please update your question and elaborate more. – Maheer Ali May 29 '19 at 07:27

score 0 · Answer 2 · answered May 29 '19 at 07:25

Use filter():

 

const providers =  [
          "1689736266",
          "1598763690",
          "1528069614",
          "1831364272",
          "1548463045",
          "1245301159",
          "1386616399",
          "1790775971",
          "1629462130",
          "1992169783"
        ];

const newArray = [1689736266, 1831364272, 123456789, 235695654 ];

const res = providers.filter(e => !newArray.includes("" + e));
console.log(res);

Get result of array elements which are not matched into a single array

2 Answers2