delete everything behind first word
sed 's/^"\([[:alpha:]]*\)[^[:alpha:]]*.*/\1/'
Match the first ". Then match a sequence of alphabetic characters. Match until you find non-alphabetic character ^[:alpha:]. Then match the rest. Substitute it all for \1 - it is a backreference for the part inside \( ... \), ie. the first word.
I need delete two “ ” with sed command
Remove all possible ":
sed 's/"//g'
Extract the string between ":
sed 's/"\([^"]*\)"/\1/'
Remove everything except alphanumeric characters (numbers + a-z + a-Z, ie. [0-9a-zA-z]):
sed 's/[^[:alnum:]]//g'