What is wrong with my code in Python Jupyter Notebook?

Question

When I run the code and input "1" or "2" it gives me the response

Sorry, we didn't understand your selection.

How do I fix this so that it gives me the correct answer?

I've Tried making "1" and "2" a string.

def cs_service_bot():
    # Replace `pass` with your code
    response = input("Hello! Welcome to the DNS Cable Company's Service Portal. Are you a new or existing customer? \n [1] New Customer \n [2] Existing Customer \n Please enter the number corresponding to your choice:")
    if response == "1":
        return new_customer()
    elif response == "2":
        return existing_customer()
    else:
        print("Sorry, we didn't understand your selection.")
        return cs_service_bot()

cs_service_bot()

No error messages, It won't give me the answer I am looking for which is either one of these functions: new_customer() or existing_customer()

Have you tried making `1` and `2` *not* a string? (Like, `if response == 1:`) — Greg Hewgill, May 30 '19 at 10:21
your code is working fine for me in both terminal and jupyter — Jeril, May 30 '19 at 10:22
@Jeril Because you are using python 3. Python 2 is having `input` and `raw_input` concepts — Harsha Biyani, May 30 '19 at 10:23
I have a similar question here too: https://stackoverflow.com/questions/56540892/game-of-chance-in-python-3-x — Da Ridg, Jun 11 '19 at 09:47

score 0 · Answer 1 · answered May 30 '19 at 10:22

Try by converting response in to string and then compare.

def cs_service_bot():
    # Replace `pass` with your code
    response = input("Hello! Welcome to the DNS Cable Company's Service Portal. Are you a new or existing customer? \n [1] New Customer \n [2] Existing Customer \n Please enter the number corresponding to your choice:")
    if str(response) == "1":
        return new_customer()
    elif str(response) == "2":
        return existing_customer()
    else:
        print("Sorry, we didn't understand your selection.")
        return cs_service_bot()

cs_service_bot()

ncica · Answer 2 · 2019-06-11T09:46:27.777

If you are using python2 ,input is returning integer, so you need do to:

response = input("Hello! Welcome to the DNS Cable Company's Service Portal. Are you a new or existing customer? \n [1] New Customer \n [2] Existing Customer \n Please enter the number corresponding to your choice:")
if response == 1:
    return new_customer()

or:

response = input("Hello! Welcome to the DNS Cable Company's Service Portal. Are you a new or existing customer? \n [1] New Customer \n [2] Existing Customer \n Please enter the number corresponding to your choice:")
if str(response) == "1":
    return new_customer()

Examples:

Python 2.x
s1 = raw_input("Enter raw_input to test raw_input() function: ")
>> 3
print (type(s1))  <type 'str'>
s11 = raw_input("Enter raw_input to test raw_input() function: ")
>> a
print (type(s11))  <type 'str'>


s2 = input("Enter input to test input() function: ")
>> 3 
print (type(s2))  <type 'int'>
s22 = input("Enter input to test input() function: ")
>> a
print (type(s22))  <type 'str'>


Python 3.x
s3 = input("Enter input to test input() function: ")
>> 1
print (type(s3))  <type 'str'>
s33 = input("Enter input to test input() function: ")
>> a
print (type(s33))  <type 'str'>

EDIT:

def new_customer():
    print ("new_customer")

def existing_customer():
    print ("existing_customer")

def cs_service_bot():
    # Replace `pass` with your code
    response = input("Hello! Welcome to the DNS Cable Company's Service Portal. Are you a new or existing customer? \n [1] New Customer \n [2] Existing Customer \n Please enter the number corresponding to your choice:")
    if response == "1":
        return new_customer()
    elif response == "2":
        return existing_customer()
    else:
        print("Sorry, we didn't understand your selection.")
        return cs_service_bot()

cs_service_bot()

output:

Hello! Welcome to the DNS Cable Company's Service Portal. Are you a new or existing customer? 
 [1] New Customer 
 [2] Existing Customer 
 Please enter the number corresponding to your choice:1
new_customer

what you are entering like input 1 with quotation marks,like "1"? @DaRidg — ncica, Jun 11 '19 at 09:26
ok thx that worked, I also have a very similar question here: https://stackoverflow.com/questions/56540892/game-of-chance-in-python-3-x — Da Ridg, Jun 11 '19 at 09:51

What is wrong with my code in Python Jupyter Notebook?

2 Answers2