How to separate each elements of a nested list and convert the list to the list of tuples?

Question

I have a nested list like below:

Zeros = [[1], [2], [3, 4], [5, 6]]

How can I separate each element and make a list of tuples, like below:

Modified_zeros = [(1), (2), (3), (4), (5), (6)]

Thanks

Answer 1

You can try iterating each element in the nested list and finally adding the single element in brackets with ,. There are other similar answers to create tuples.

results = [(j,) for i in Zeros for j in i]

Output:

[(1,), (2,), (3,), (4,), (5,), (6,)]

Answer 2

Based off this answer:

flat_list = [(item,) for sublist in l for item in sublist]

Where l is your original list (Zeros in your case)

Answer 3

for nested list at multiple level

Zeros = [[1], [2], [3, 4], [5, 6,[1,2,3,4]]]

def fun(l):
    res=[]
    if isinstance(l,list):
        for i in l:
            res.extend(fun(i))
    elif isinstance(l,int):
        res.append((l,))
    return res

print(fun(Zeros))

output

[(1,), (2,), (3,), (4,), (5,), (6,), (1,), (2,), (3,), (4,)]