I want to convert an integer into a string of numeric characters in C.
I've tried using itoa, but it's non-standard and not provided by my C library.
I tried to implement my own itoa, but it's not working properly:
#include <stdlib.h>
#include <stdio.h>
char *itoa(int val, char *buf, int base)
{
    size_t ctr = 0;
    for( ; val; val /= base )
    {
        buf[ctr++] = '0' + (val % base);
    }
    buf[ctr] = 0;
    return buf;
}
int main(void)
{
    unsigned char c = 201;
    char *buf = malloc(sizeof(c)*8+1);
    itoa(c, buf, 2);
    puts(buf);
    free(buf);
}
It gives reversed output.
For example, if c is 'A' and base is 2, the output is this: 0101101
The output I want it to be is this: 1011010
How do I fix this issue?
Similar questions
I've already seen this question: Is there a printf converter to print in binary format?
I do not want a printf format specifier to print an integer as binary, I want to convert the binary to a string.
I've already seen this question: Print an int in binary representation using C
Although the answer does convert an integer into a string of binary digits, that's the only thing it can do.
Restrictions
I want itoa to be able to work with other bases, such as 10, 8, etc. and print correctly (i.e. 12345 translates to "12345" and not to "11000000111001").
I do not want to use printf or sprintf to do this.
I do not care about the length of the string as long is the result is correct.
I do not want to convert the integer into ASCII characters other than numeric ones, with the exception of bases greater than 10, in which case the characters may be alphanumeric.
The answer must fit this prototype exactly:
char *itoa(int val, char *buf, int base);
There may be a function called nitoa that has this prototype and returns the number of characters required to hold the result of itoa:
size_t nitoa(int val, int base);
 
    