Remove object from array of objects based on object key value

Question

I have an object like

let arr = [
    {isManaged: true, id:1},
    {isManaged: false, id:2},
    {isManaged:false, id:3}
]

to get the values which are true, i do

arr.map(shift => ({
    id: shift.id,
    isPartnerManaged: shift.isManaged,
}))

but this will only return me the values where i true, now, I want to remove them from the array of objects. I tried to use the array.pop but i don't know what index to feed it. Any ideeas?

Possible duplicate of [Filter an array based on an object property](https://stackoverflow.com/questions/35231008/filter-an-array-based-on-an-object-property) — str, Jun 13 '19 at 12:08

score 3 · Accepted Answer · answered Jun 13 '19 at 12:08

3

arr = arr.filter(shift => shift.isManaged);

answered Jun 13 '19 at 12:08

horia

419
4
17

score -1 · Answer 2 · answered Jun 13 '19 at 12:10

You could filter the array and build new objects.

var array = [{ isManaged: true, id: 1 }, { isManaged: false, id: 2 }, { isManaged: false, id: 3 }],
    result = array
        .filter(({ isManaged }) => isManaged)
        .map(({ isManaged: isPartnerManaged, id }) => ({ id, isPartnerManaged }));

console.log(result);

Remove object from array of objects based on object key value

2 Answers2