can a single dimension array made to point to the first address of a three dimensional array,
e.g.
int *array;
int ***array3D;
array=*array3D;
I need the first array to point to the first address of the second array.
I need only the first address into the pointer. Can anyone please suggest any alternatives to point to the starting address? Thanks in advance.
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harsha
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Need to format the code and re post it. Also you can not dereference `void*`. Give example of any other data type. – iammilind Apr 16 '11 at 11:42
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@iammilind: But you can dereference `void **` or `void ***`. – Oliver Charlesworth Apr 16 '11 at 11:49
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Do you want to point at the *address* of the first element (i.e. point at the pointer), or point at the first element *itself*? – Oliver Charlesworth Apr 16 '11 at 11:50
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This http://stackoverflow.com/questions/62512/three-dimensional-arrays-of-integers-in-c related question might provide you with some insights – celavek Apr 16 '11 at 11:56
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This kind of thing happens all the time when you're processing 2D and 3D images.
That you wrote (array = *array3D) obviously won't compile though because the types don't match. array3D is an **int and array is an *int.
If you have array3D set up correctly, as such (for example):
int ***array3D = new int **[zsize];
for(int z = 0 ; z < zsize ; ++z)
{
array3D[z] = new int *[ysize];
for(int y = 0 ; y < ysize ; ++y)
{
array3D[z][y] = new int [xsize];
}
}
Then you can access things like array3D[z][y] (points to the x=0 element for the given z and y)
or &(array3D[z][y][x]) (points to element x, y, z)
or *(array3D[z]) (points to the y=0 and x=0 element for the given z), and will then all be of type int *. I suggest writing out how your data is organized.
Of course you have to manually delete this structure as well and if you're doing this in a product, you should be careful that you handle exceptions well and don't leak, but this another topic.
Chris A.
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