Problem with extracting multiple segments

Question

I'm trying to capture the bellow parts from the attached log:

aff_lsr?tt_adv_id=806&tt_cid=&tt_adv_sub=b3fff3722fc6b52aedde9b86bb22bf23&tt_time=2016-04-05+16%3A08%3A18&

should capture:

●   tt_adv_id
●   806
●   tt_adv_sub 
●   b3fff3722fc6b52aedde9b86bb22bf23
●   tt_time
●   2016-04-05+16%3A08%3A18

I have tried to create a regex to extract all strings which start with either “?” “&” or “=” and end with either “=” or “&”

this is the regex I have tried:

(?=[?/&/=]).*?(=)|(?=[=/&])

it ignores all parts between “=” and “&”

so the result i get is :

?tt_adv_id =

&tt_cid=

&tt_adv_sub=

&tt_time =

the string is always in given format ? it seems as query parameters of URL — Code Maniac, Jul 06 '19 at 06:33

Emma · Answer 1 · 2019-07-07T05:33:57.900

Maybe, these simple expressions would extract our desired values:

.*(tt_adv_id)=([^&]*)&(?:tt_cid)=(?:[^&]*)&(tt_adv_sub)=([^&]*)&(tt_time)=([^&]*).*

or

(tt_adv_id)=([^&]*)&(?:tt_cid)=(?:[^&]*)&(tt_adv_sub)=([^&]*)&(tt_time)=([^&]*)

The expression is explained on the top right panel of this demo, if you wish to explore further or modify it, and in this link, you can watch how it would match against some sample inputs step by step, if you like.

const regex = /.*(tt_adv_id)=([^&]*)&(?:tt_cid)=(?:[^&]*)&(tt_adv_sub)=([^&]*)&(tt_time)=([^&]*).*/gm;
const str = `aff_lsr?tt_adv_id=806&tt_cid=&tt_adv_sub=b3fff3722fc6b52aedde9b86bb22bf23&tt_time=2016-04-05+16%3A08%3A18&
`;
let m;

while ((m = regex.exec(str)) !== null) {
    // This is necessary to avoid infinite loops with zero-width matches
    if (m.index === regex.lastIndex) {
        regex.lastIndex++;
    }
    
    // The result can be accessed through the `m`-variable.
    m.forEach((match, groupIndex) => {
        console.log(`Found match, group ${groupIndex}: ${match}`);
    });
}

hi, do you know how to capture it into 6 different groups ? – Dror Yelin Jul 07 '19 at 05:20 — Dror Yelin, Jul 07 '19 at 05:20

Code Maniac · Answer 2 · 2019-07-06T06:45:36.763

0

You can simply use

/[?&=]([^&=]+)/

[?&=] - Match ?, & or =
([^&=]+) - Match anything except & and = one or more time

and than drop off the first character of each match,

let str = "aff_lsr?tt_adv_id=806&tt_cid=&tt_adv_sub=b3fff3722fc6b52aedde9b86bb22bf23&tt_time=2016-04-05+16%3A08%3A18&"

let matched = str.match(/[?&=]([^&=]+)/g).map((v)=>v.substr(1))

console.log(matched)

edited Jul 06 '19 at 06:45

answered Jul 06 '19 at 06:39

Code Maniac

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Thanks , it works but I do need to 6 different capture groups – Dror Yelin Jul 06 '19 at 08:25

Problem with extracting multiple segments

2 Answers2