Python: find the word in string

Question

I want to find the word in string like this below:

kkk="I do not like that car."

if "like" in kkk:
    print("like")
elif "dislike" in kkk:
    print("dislike")
elif "hate" in kkk:
    print("hate")
elif "cool" in kkk:
    print("cool")

But since my code is very long, I would like to keep it shorter:

if "like" in kkk or "dislike" in kkk or "hate" in kkk or "cool" in kkk:
    #print "like" 
    #unable to do it this way

Then I tried to use another way, but it didn't work:

a=["like","dislike","hate","cool"]

if any(x in kkk for x in a):
    print(x)
    #NameError: name 'x' is not defined

why not a simple `for-loop` --> `for x in a: if x in kkk: print(x)` ? — Rakesh, Jul 10 '19 at 07:54

score 1 · Answer 1 · answered Jul 10 '19 at 07:55

1

Try this :

>>> kkk="I do not like that car."
>>> a=["like","dislike","hate","cool"]
>>> print(*[x for x in a if x in kkk])
like

This list comprehension is same as the following :

for x in a:
    if x in kkk:
        print(x)

answered Jul 10 '19 at 07:55

Arkistarvh Kltzuonstev

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score 0 · Answer 2 · answered Jul 10 '19 at 07:54

0

Use a for loop that iterates over the list. And change your variable names to something more meaningful.

kkk="I do not like that car."
wordlist =["like","dislike","hate","cool"]
for word in wordlist:
    if word in kkk:
         print(word)

answered Jul 10 '19 at 07:54

Syrius

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deceze · Answer 3 · 2019-07-10T08:12:11.087

0

any won't return the found word; the best alternative is perhaps next:

keywords = ["like", "dislike", "hate", "cool"]
sentence = "I do not like that car."

try:
    word = next(k for k in keywords if k in sentence)
    print(word)
except StopIteration:
    print('Not found')

If you don't want to handle an exception and instead get None:

word = next((k for k in keywords if k in sentence), None)

edited Jul 10 '19 at 08:12

answered Jul 10 '19 at 07:57

deceze

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score 0 · Answer 4 · answered Jul 10 '19 at 07:57

0

another way of doing this is using sets:

kkk="I do not like that car."
kkk_split = kkk.split(' ')
print({'like', 'dislike', 'hate', 'cool'}.intersection(kkk_split))

answered Jul 10 '19 at 07:57

Nullman

4,179
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Note that `split` and set intersection won't necessarily yield the same result as `in`. – deceze Jul 10 '19 at 07:59
@deceze how so? – Nullman Jul 10 '19 at 07:59
1

`'like' in 'He likes cars'` vs. `{'like'}.intersection({'He', 'likes', 'cars'})`… – deceze Jul 10 '19 at 08:00
indeed it does not work for sub-strings, but i think the author was asking for full words – Nullman Jul 10 '19 at 10:40

score 0 · Answer 5 · answered Jul 10 '19 at 09:26

For your case, in keyword cause conflicting result. For example, the snippet below:

sentence = "I do dislike that car."
opinion = ["like","dislike","hate","cool"]
for word in opinion:
    if word in sentence:
        print(word)

prints both like and dislike. Instead, you can use regular expression zero-width word boundary \b for accurate result as:

import re

sentence = "I do dislike that car."
opinion = ["like","dislike","hate","cool"]
for word in opinion:
    if re.search(r'\b'+word+r'\b', sentence):
        print(word)

which prints dislike only.

Python: find the word in string

5 Answers5

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