I have this in an async function:
const result = knexnest(customerProducts).then(data => data);
return result;
Should it be changed to this:
const result = await knexnest(customerProducts);
return result;
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runnerpaul
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Just return the call? `return knexnest(customerProducts)` – CertainPerformance Jul 13 '19 at 10:48
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Doesn't matter. Both do the same (as long as there is not `try ... catch` around. Also `.then(data => data)` is useless. – Jonas Wilms Jul 13 '19 at 10:48
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1[How do I return the response from an asynchronous call](https://stackoverflow.com/questions/14220321/how-do-i-return-the-response-from-an-asynchronous-call) – Andreas Jul 13 '19 at 10:49
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Do you mean ES2015 (aka ES6)? – Bergi Jul 13 '19 at 12:14