Is there any way how to find elements of array by multiple values?

Question

I have an array:

people = [
  {name: a, group: 1},
  {name: b, group: 2},
  {name: c, group: 3},
  {name: d, group: 2},
  {name: e, group: 3},
  {name: f, group: 1},
  {name: g, group: 1},
];

I need to find all people, who are in groups 2 and 3. Desired output:

filteredPeople = [
  {name: b, group: 2},
  {name: c, group: 3},
  {name: d, group: 2},
  {name: e, group: 3},
];

It might be other groups as well (groups using for search may change).

How I have to do that?

`filteredPeople = people.filter(i => [2,3].includes(i.group));`...? — briosheje, Jul 25 '19 at 09:02
Possible duplicate of [filtering an array of objects based on another array in javascript](https://stackoverflow.com/questions/46894352/filtering-an-array-of-objects-based-on-another-array-in-javascript) and [Filter array of objects by multiple values](https://stackoverflow.com/questions/53576285) and [Filter array of objects by multiple properties and values](https://stackoverflow.com/questions/44330952) — adiga, Jul 25 '19 at 09:05

score 1 · Answer 1 · answered Jul 25 '19 at 09:03

You can use .filter() and .includes() methods to get the desired output:

const data = [
  {name: 'a', group: 1}, {name: 'b', group: 2}, {name: 'c', group: 3},
  {name: 'd', group: 2}, {name: 'e', group: 3}, {name: 'f', group: 1},
  {name: 'g', group: 1}
];

const groups = [2, 3];

const result = data.filter(({ group }) => groups.includes(group));

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

claasic · Answer 2 · 2019-07-25T09:12:31.073

filter and includes do the job here. We use the rest operators (which gives us an array on which we can apply includes). So you can put any number of groups into the function call to be flexible when filtering.

let people = [{name: "a",group:1},{name: "b",group:2},{name: "c",group:3},{name:"d",group:2},{name:"e",group:3},{name:"f",group:1},{name:"g",group:1}];

let filterGroups = (arr, ...groups) => arr.filter(o => groups.includes(o.group));

console.log(filterGroups(people, 2, 3));

score 0 · Answer 3 · answered Jul 25 '19 at 09:09

Using Array.prototype.filter() and the expression 2 === group || group === 3

const data = [{name: 'a', group: 1}, {name: 'b', group: 2}, {name: 'c', group: 3}, {name: 'd', group: 2}, {name: 'e', group: 3}, {name: 'f', group: 1}, {name: 'g', group: 1}];
const result = data.filter(({ group }) => group === 2 || group === 3);

console.log(result);

Is there any way how to find elements of array by multiple values?

3 Answers3