In my project, I needed to insert two elements into two indices. I was implementing an alternative implementation instead of vector insert since two insert calls shift vector elements twice and I can do the same with a single shift. However, the alternative is far slower. What could be the explanation of this behavior?
#include <vector>
#include <chrono>
#include <iostream>
void insert2(std::vector<int>& items, size_t first, size_t last, int item = -1) {
    // assert(last < items.size() + 2);
    // assert(first < last);
    // assert(0 <= first);
    // Creating two temporary objects
    // items.reserve(std::max(items.capacity(), items.size() + 2));
    items.emplace_back(); items.emplace_back();
    // Moving elements from the back to last
    for(auto p = items.end() - 1, q = items.begin() + last; p != q; --p) {
        // *p = std::move(*(p - 2));
        *p = *(p - 2);
    }
    // Emplace at last
    // new(&items[last]) ...
    items[last] = item;
    // Moving elements from last to first
    for(auto p = items.begin() + last - 1, q = items.begin() + first; p != q; --p) {
        // *p = std::move(*(p - 1));
        *p = *(p - 1);
    }
    // Emplace at first
    // new(&items[first]) ...
    items[first] = item;
}
auto now() {
    return std::chrono::steady_clock::now();
}
int main() {
    const size_t N = 100;
    const size_t M = 100;
    auto begin = now();
    begin = now();
    for(size_t n = 0; n < N; n++) { // run the same N times
        for(size_t i = 0; i < M + 1; i++) {
            for(size_t j = i + 1; j < M + 2; j++) {
                std::vector<int> v(M);
                insert2(v, i, j);
            }
        }
    }
    std::cout << "insert2 " << std::chrono::duration_cast<std::chrono::nanoseconds>(now() - begin).count() / (1000.0 * N) << "us\n";
    begin = now();
    for(size_t n = 0; n < N; n++) { // run the same N times 
        for(size_t i = 0; i < M + 1; i++) {
            for(size_t j = i + 1; j < M + 2; j++) {
                std::vector<int> v(M);
                v.insert(v.begin() + i, -1);
                v.insert(v.begin() + j, -1);
            }
        }
    }
    std::cout << "insert1 " << std::chrono::duration_cast<std::chrono::nanoseconds>(now() - begin).count() / (1000.0 * N) << "us\n";
}
My Intel(R) Core(TM) i7-3770 CPU @ 3.40GHz outputs with O0
insert2 7941.29us
insert1 4005.15us
With O3,
insert2 763.64us
insert1 688.365us
 
    