Binning objects based on value of attribute in Python

Question

I see similar questions asked for Java and PHP, but couldn't find a way to it in python3.

I have the following object:

object{
    id
    time
}

Assume that time is between 0-1000

I have created a list of instances of this object.

{['idA', 33], ['idB', 68], ['idC', 453], ['idD', 3], ...}

I have also have a list of bins:

bins = numpy.linspace(0, 1000, 100)

>>> array([   0.        ,   10.1010101 ,   20.2020202 ,   30.3030303 ,
         40.4040404 ,   50.50505051,   60.60606061,   70.70707071,
         80.80808081,   90.90909091,  101.01010101,  111.11111111,
        121.21212121,  131.31313131,  ... 989.8989899 , 1000.        ])

My question: I want to put the objects in the list into bins based on the values given above. I can do this using a for loop.

But is there a easier/cleaner way that this can be done? Particularly I am looking for something like this that I found here:

# To sort the list in place...
ut.sort(key=lambda x: x.count, reverse=True)

# To return a new list, use the sorted() built-in function...
newlist = sorted(ut, key=lambda x: x.count, reverse=True)