compare two object and log values that do not exist with angular

Question

I'm trying to compare two objects with the purpose of logging out the ones which do not exist in the first object.

First Object

this.Object1 =[{id:1, name,'Coke'}, {id:2, name,Fanta},{id:3, name,'Sprite'}, {id:4, name,'Pepsi'}]

Second Object

this.Object 2 = [{id:1, name,'Coke'}, {id:2, name,'Fanta'},{id:5, name,'Miranda'}, {id:6, name,'Alvaro', id:7, 'Orange Juice'}]

What I want to achieve is to loop through object1 and find their ids that don't exist in object2 and push those in there

so the final result of object1 will be like this

[{id:1, name,'Coke'}, {id:2, name,Fanta},{id:3, name,'Sprite'}, {id:4, name,'Pepsi',id:5, name,'Miranda'}, {id:6, name,'Alvaro', id:7, 'Orange Juice'}]

Script

for (let r = 0; r < this.object1.length; r++) {
  for (let i = 0; i < this.object2.length; i++) {
      if (this.object1.id != this.object2[i].id) {
      this.object2.push(this.object1[r]);
      console.log(this.object1[i].name  + ' does not exist');
      }
  }
}

score 2 · Accepted Answer · answered Aug 12 '19 at 06:30

Can you try this? it may help you

obj1 = [{id:1, name:'Coke'}, {id:2, name: 'Fanta'},{id:3, name: 'Sprite'}, {id:4, name:'Pepsi'}]
obj2 = [{id:1, name:'Coke'}, {id:2, name:'Fanta'},{id:5, name:'Miranda'}, {id:6, name:'Alvaro'},{ id:7, name: 'Orange Juice'}]
ids = []
obj1.map(res => {ids.push(res.id)})
obj2.map(res => {
    if(!ids.includes(res.id)){
        obj1.push(res)
    }
})
// [ { id: 1, name: 'Coke' }, { id: 2, name: 'Fanta' }, { id: 3, name: 'Sprite' }, { id: 4, name: 'Pepsi' }, { id: 5, name: 'Miranda' }, { id: 6, name: 'Alvaro' }, { id: 7, name: 'Orange Juice' } ]

score 0 · Answer 2 · edited Aug 12 '19 at 06:35

0

Could you try this

var o = [{id:1, name:'Coke'}, {id:2, name:'Fanta'},{id:3, name:'Sprite'}, {id:4, name:'Pepsi'}];
var oo= [{id:1, name:'Coke'}, {id:5, name:'ZZZ'}, {id:6, name:'YYY'}, {id:9, name:'XXX'}, {id:4, name:'Pepsi'}];

var unique = oo.filter(x=>o.findIndex(y=>y.id===x.id)===-1);

console.log(unique);
var all = o.concat(unique);

edited Aug 12 '19 at 06:35

Prashant Pimpale

10,349
9
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answered Aug 12 '19 at 06:21

kunal verma

456
5
13

score 0 · Answer 3 · answered Aug 12 '19 at 06:33

You have some issues/tyops in your objects. {id:3, name,'Sprite'}needs to be {id:3, name: 'Sprite'} for example. When this is fixed you can write something like this if using es6:

const arr1 = [
  {id:1, name:'Coke'},
  {id:2, name: 'Fanta'},
  {id:3, name: 'Sprite'},
  {id:4, name: 'Pepsi'}
]

const arr2 = [
  {id:1, name: 'Coke'}, 
  {id:2, name: 'Fanta'},
  {id:5, name: 'Miranda'}, 
  {id:6, name: 'Alvaro'},
  {id:7, name: 'Orange Juice'},
]

const getIds = (arr) => arr.map(i => i.id)

const diff = getIds(arr2).filter((item) => getIds(arr1).includes(item))

console.log('Diff:', diff)

compare two object and log values that do not exist with angular

3 Answers3