Nested class in templated class used in templated function syntax error

Question

Suppose I have the following:

template<typename T>
    struct Foo
    {
    public:
        class Bar
        {           
        };
    };

If I then define the function

template <typename T>
void func(Foo<T>::Bar g) { }

I get an error: syntax error: identifier 'Bar'

Why do I get the error and how can I solve it so that I can use the templated function.

`void func(typename Foo::Bar g) { }` – Eljay Aug 14 '19 at 12:27 — Eljay, Aug 14 '19 at 12:27

Vlad from Moscow · Accepted Answer · 2019-08-14T13:31:49.397

0

Use

template <typename T>
void func( typename Foo<T>::Bar g ) { }

Otherwise the construction Foo<T>::Bar is not considered by the compiler as a type specifier but as an expression.

edited Aug 14 '19 at 13:31

answered Aug 14 '19 at 12:29

Vlad from Moscow

How about adding a few words on why the snippet in the question did not work in the first place? – ndrwnaguib Aug 14 '19 at 13:28

1 Answers1