Why regex fail when I used lowercase?

Question

Could you please tell me why my regex test fails when I use a lowercased a?

Here is my code:

  var a = "A0201418"

  if (/^A\d{7}$/.test(a)) {
      console.log('=====true');
  } else {
      console.log('false');
  }

Expected output "A0201418" . true
"a0201418" . true .

I want a pattern where start with "A" follow with 7 digit number

score 2 · Accepted Answer · answered Aug 29 '19 at 05:10

2

Use the case-insensitive flag (i):

if (/^A\d{7}$/i.test(a)) {...}

If you're using the RegExp constructor, pass "i" as the second argument:

RegExp("^A\\d{7}$", "i")

answered Aug 29 '19 at 05:10

Jack Bashford

Joseph, please don't try to edit my code - comment it, and if I see it'll improve the quality of the post, I'll change it. – Jack Bashford Aug 29 '19 at 05:17

1 Answers1