How to change selected segment color in SwiftUI Segmented Picker

Question

I want to set the selected segment color in a SwiftUI segmented picker and change the text color to white.

I have tried both using the modifiers for the picker view and modifying the tint color from the appearance proxy. None of them seem to work, unfortunately.

import SwiftUI

struct PickerView: View {

    @State var pickerSelection = 0

    init() {
        UISegmentedControl.appearance().tintColor = UIColor.blue
    }

    var body: some View {
        Picker(selection: $pickerSelection, label: Text("")) {
            Text("Active").tag(0).foregroundColor(Color.white)
            Text("Completed").tag(1)
        }.pickerStyle(SegmentedPickerStyle()).foregroundColor(Color.orange)
    }
}

Is there any way to do this in SwiftUI, or should I just use the UISegmentedControl by using UIViewControllerRepresentable?

Answer 1

Native ( but limited )

SwiftUI is not currently supporting native SegmentedPicker styling (see the bottom of the answer for the working workaround). But there is a limited way to apply a color to the segmented picker using .colorMultiply() modifier:

---

Full control using UIAppearance

selectedSegmentTintColor is available since beta 3 for changing the color of the selected segment.

For changing the textColor, you should use setTitleTextAttributes for .selected state and .normal state (unselected).

So it will be like:

init() {
    UISegmentedControl.appearance().selectedSegmentTintColor = .blue
    UISegmentedControl.appearance().setTitleTextAttributes([.foregroundColor: UIColor.white], for: .selected)
    UISegmentedControl.appearance().setTitleTextAttributes([.foregroundColor: UIColor.blue], for: .normal)
}

Also as mike mentioned, you can set the background color too like:

UISegmentedControl.appearance().backgroundColor = .yellow

Also, don't forget you can set SwiftUI colors too! For example:

UISegmentedControl.appearance().selectedSegmentTintColor = UIColor(Color.accentColor)

Answer 2

Recently I had a similar issue that I needed a custom background and foreground colors for SwiftUI SegmentedControl I've found this post that also was helpful, but I also wanted to share other solution that I've found and I'm using now. There is a very nice package called SwiftUI Introspect that allows to, well...

Introspect underlying UIKit components from SwiftUI

With this package I created the following SegmentedControl With this code:

VStack {
    Picker("Activity view", selection: $selectedActivity) {
        ForEach(ActivityView.allCases) { activity in
            Text(activity.description)
        }
    }
    .introspectSegmentedControl { segmentedControl in
        segmentedControl.backgroundColor = .clear
        segmentedControl.tintColor = TCHColors.SegmentedControl.backgroundSelected
        segmentedControl.selectedSegmentTintColor = TCHColors.SegmentedControl.backgroundSelected
        segmentedControl.setTitleTextAttributes([
            NSAttributedString.Key.foregroundColor: TCHColors.SegmentedControl.selectedText
        ], for: .selected)
        segmentedControl.setTitleTextAttributes([
            NSAttributedString.Key.foregroundColor: TCHColors.SegmentedControl.normalText
        ], for: .normal)
    }
    .pickerStyle(.segmented)
}
.padding(.horizontal, 16)

And you can use this package to access many other underlying components from SwiftUI.

Answer 3

Here is a manual implementation of segmented picker functionality:

@ViewBuilder func viewSegmentedButtons(arr: [String], selIndex: Int, baseColor: Color, closure:@escaping (_ selectedIndex: Int) -> Void) -> some View {
    
    let columns = Array(repeating: GridItem(spacing: 1), count:arr.count)
    LazyVGrid(columns: columns, spacing: 1.0) {
        ForEach(Array(arr.enumerated()), id: \.element) { index, translation in
            Button {
                closure(index)
            } label: {
                ZStack {
                    Rectangle()
                        .foregroundColor(index == selIndex ? baseColor : Color(.systemBackground))
                        .cornerRadius(radius: index==0 ? cRadius : 0, corners: [.topLeft, .bottomLeft])
                        .cornerRadius(radius: index==arr.count-1 ? cRadius : 0, corners: [.topRight, .bottomRight])
                    Text(translation)
                        .padding(.vertical, 10)
                        .font(.footnote)
                        .foregroundColor(index != selIndex ? baseColor : Color(.systemBackground) )
                }
            }
        }
    }
    .foregroundColor(baseColor)
    .overlay(
        RoundedRectangle(cornerRadius: cRadius)
            .stroke(baseColor, lineWidth: 2)
    )
    .font(.callout)
    .background(baseColor)
    .cornerRadius(cRadius)
    .padding(.bottom, 10)
}

Usage example:

@State private var levelIndex: Int = 0
var body: some View {
    VStack {
        Text("Level:")
        
        viewSegmentedButtons(arr: ["Easy", "Meduim", "Hard"], selIndex: levelIndex, baseColor: .orange) { selectedIndex in
            withAnimation {
                levelIndex = selectedIndex
            }
        }
    }
}

Result:

Answer 4

This answered helped me, but there is something I would like to add. The color I used was an argument to the view, so placing these methods in an init did not allow me to access the color.

Alternatively, you can use an onAppear method directly on the Segmented Picker, like so.

import SwiftUI

struct PickerView: View {
    var color: UIColor   
    @State var pickerSelection = 0

    var body: some View {
        Picker(selection: $pickerSelection, label: Text("")) {
            Text("Active").tag(0).foregroundColor(Color.white)
            Text("Completed").tag(1)
        }.pickerStyle(SegmentedPickerStyle()).foregroundColor(Color.orange)
        .onAppear {
            UISegmentedControl.appearance().tintColor = color
        }
    }
}

Answer 5

Here is my solution that works in SwiftUI:

init(){

    UISegmentedControl.appearance().selectedSegmentTintColor = .green
    UISegmentedControl.appearance().setTitleTextAttributes([.foregroundColor: UIColor.black], for: .selected)

    }