print incremental count variable val within while

Question

Below is what I currently have; I am not sure why I cannot just print the value, incrementally with the below; i.e. 1,2,3.. etc. I have also tried cout<<count;

 #include <iostream>
    using namespace std;
    int main()
    {char count;


     while(count<=10)
     {
     cout<<"My name is Bill"<<endl;
     cout << "The # is:" <<count<<endl;
     cout << count++;
     }
     }

What happens when you run this code? What do you want it to do differently? — Code-Apprentice, Sep 04 '19 at 16:41
Could you please explain a little more? It is very unclear to me what you are asking — NathanOliver, Sep 04 '19 at 16:43
You use `count` uninitialized and you need to cast it for it to be visible: `cout << static:cast(count++);` — Ted Lyngmo, Sep 04 '19 at 16:46

score 4 · Answer 1 · answered Sep 04 '19 at 16:43

4

count is uninitialized. Since you want to start from 1, you should initialize it that way. And, you should use an integer.

int count=1;

answered Sep 04 '19 at 16:43

jxh

69,070
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score 3 · Answer 2 · answered Sep 04 '19 at 16:43

You should declare count as an int and initialize it:
```
int count = 0;
```
I suggest you learn about the different primitive data types that C++ has. Using the correct type for what you want to do will save you a lot of headache.
You are incrementing and printing out with one command:
```
cout << count++;
```
Instead, you only need to increment:
```
count++;
```

print incremental count variable val within while

2 Answers2