How can i get access to static method through variable?

Question

Trying to get

$class = 'MyClass';
$class::classname() - MyClass not found

So, is it possible? Or are there other options?

public function actionMultiUpdate($module)
{
    if (isset($_REQUEST['multiedit']) && count($_REQUEST['multiedit'])) {
        foreach ($_REQUEST['multiedit'] as $id => $data) {
            $model = $module::findOne($id);
            $model->weight = $data['weight'];
            $model->save();
        }
    }
}

Try looking at: https://www.php.net/manual/en/functions.variable-functions.php — Umair Shah, Sep 05 '19 at 04:30
Also this as well: https://www.php.net/manual/en/function.call-user-func.php — Umair Shah, Sep 05 '19 at 04:30
Take a look at this as well: https://www.php.net/manual/en/language.oop5.paamayim-nekudotayim.php — Umair Shah, Sep 05 '19 at 04:43

Maksym Fedorov · Accepted Answer · 2019-09-05T07:32:10.977

-1

You can use call_user_func to run a static method with the string class name. For example:

class Myclass
{

    public static function classname() {
        return __CLASS__;
    }
}

$class = 'MyClass';
echo call_user_func([$class, 'classname']);

Also if you want to pass variables into a static method you should pass them in the second parameter. For example:

class MyClass
{
    public static function doSomething($value1, $value2)
    {
        return $value1 . ' and ' . $value2;
    }
}

$class = 'MyClass';
echo call_user_func([$class, 'doSomething'], 'first value', 'second value');

edited Sep 05 '19 at 07:32

answered Sep 05 '19 at 07:17

Maksym Fedorov

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How can i pass variable into method? – Evgeny Musonov Sep 05 '19 at 07:28
I think it works, but in yii2 isn't. Maybe you know solution in this framework? – Evgeny Musonov Sep 05 '19 at 07:48
@EvgenyMusonov Can you attach your code which you try to run to the answer? – Maksym Fedorov Sep 05 '19 at 07:57
you can see it in the topic – Evgeny Musonov Sep 05 '19 at 07:59
I don't see code with using call_user_func in the question and I don't know what data is used – Maksym Fedorov Sep 05 '19 at 08:02
`public function actionMultiUpdate($module) { if (isset($_REQUEST['multiedit']) && count($_REQUEST['multiedit'])) { foreach ($_REQUEST['multiedit'] as $id => $data) { $model = call_user_func([$class, 'findOne'], $id); //$model = MainMenu::findOne($id); $model->weight = $data['weight']; $model->save(); } } }` – Evgeny Musonov Sep 05 '19 at 08:07
@EvgenyMusono it looks right. so what an error do you get? – Maksym Fedorov Sep 05 '19 at 08:10
PHP Warning – yii\base\ErrorException call_user_func() expects parameter 1 to be a valid callback, class 'MainMenu' not found – Evgeny Musonov Sep 05 '19 at 08:11
@EvgenyMusonov your $module variable must contain full name of the class with namespace. – Maksym Fedorov Sep 05 '19 at 08:12

score -1 · Answer 2 · answered Sep 05 '19 at 07:37

You can put the class name in a variable and call it with the method, or put the class name and method into a variable and then call it. It is also possible to use call_user_func ().

class Myclass{
  public static function myMethod(){
    return "return from Myclass::myMethod";
  }
}

//only class name in a variable
$curClass = 'Myclass';
echo $curClass::myMethod();

//class and Method in a variable
$classAndmethod = 'Myclass::myMethod';
echo $classAndmethod();

tested with php 7.2.21.

How can i get access to static method through variable?

2 Answers2