In python, how to ignore an exception and process odd code?

Question

sample:

with suppress(Exception)
    os.remove('test1.log')
    os.remove('test2.log')

try:
    os.remove('test1.log')
    os.remove('test2.log')
except:
    pass

test2.log will not be deleted if test1.log isn't exist because FileNotFoundError. So how to process odd code after an exception happened, or how to prevent an exception been throw?

Possible duplicate: https://stackoverflow.com/questions/730764/how-to-properly-ignore-exceptions — Sparky05, Sep 10 '19 at 08:54

score 0 · Answer 1 · answered Sep 10 '19 at 08:33

In a try-except if an exception is triggered, it will go the the except part than continue from there. So if you want to make sure both remove are attempted, do this:

try:
    os.remove('test1.log')
except:
    pass

try:
    os.remove('test2.log')
except:
    pass

Alternatively, you can try checking if the file exists, before deleting it:

if os.path.exists('test1.log'):
   os.remove('test1.log')
if os.path.exists('test2.log'):
   os.remove('test2.log')

score 0 · Answer 2 · answered Sep 10 '19 at 08:37

0

As the duplicate explains, you can't just suppress the exceptions.

You probably want something like this:

files = ["test1.log", "test2.log"]
for file in files:
    try:
        os.remove(file)
    except:
        pass

answered Sep 10 '19 at 08:37

Mars

2,505
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score 0 · Answer 3 · answered Sep 10 '19 at 08:40

tituszban already gave a valid solution. You could also simply put your statements into a for-loop, which is shorter syntax since you don't have to repeat your try-catch blocks (especially useful when trying to delete more than 2 items).

lst = ["test1.log","test2.log"]
for element in lst:
    try:
        os.remove(element)
    except:
        pass

In python, how to ignore an exception and process odd code?

3 Answers3