I recently came across this code snippet . This code prints Hello as output. I don't know the reason Why?

Question

I think this code should give Error. But it gives me Hello as Output.

public class Main
{
    public static void main(String[] args) {
        foo(null);
    }

    public static void foo(String str){
        System.out.println("Hello");
   }

    public static void foo(Object o){
       System.out.println("Hi");
   }
}

Have a look at https://stackoverflow.com/questions/1545501/which-overload-will-get-selected-for-null-in-java — i.bondarenko, Sep 22 '19 at 09:36

Yennefer · Answer 1 · 2019-09-22T09:41:41.513

3

String is a nullable type, therefore your call to foo(String) can take place.

Additionally, the overload resolution rule states that the "most specific" type takes the precedence, hence the string overload is chosen.

edited Sep 22 '19 at 09:41

answered Sep 22 '19 at 09:35

Yennefer

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1

You are right;) I was thinking in C#, in fact in java is not correct. I amend the answer. – Yennefer Sep 22 '19 at 09:41

I recently came across this code snippet . This code prints Hello as output. I don't know the reason Why?

1 Answers1