Why the first if statement conditional is ignored and the last else is executed?

Question

When I type in John and 0 the "John is great" statement is not executed. I don't understand why.
I know that the question might be really simple but I checked the code in Java and it was working correctly.

print("Hello world")
myName = input("What is your name?\n")
myVar = input("Enter a number: ") 

if(myName == "John" and myVar == 0):
    print("John is great")
elif(myName == "Bob"):
    print("You are ok")
else:
    print("Hello world")

Both variables are `str` values; you are comparing one of them to an *`int`*, so that is always false. — chepner, Sep 27 '19 at 16:37
Yes. All inputs are strings. If you want to read an input as integer, you have to do a cast: `myvar = int(input("Enter a number: "))`. — Julia K, Sep 27 '19 at 16:39

luthierBG · Answer 1 · 2019-09-27T16:50:09.463

3

myVar is str type. Not int type.
You should fix myVar = int(input("Enter a number: "))

edited Sep 27 '19 at 16:50

answered Sep 27 '19 at 16:39

luthierBG

164
1
9

score 0 · Answer 2 · answered Sep 27 '19 at 16:38

0

0 and "0" are two different values. 0 == 0 is true; 0 == "0" is false.

input always returns a str, so entering 0 sets myVar to "0", not 0.

if myName == "John" and myVar == "0":

answered Sep 27 '19 at 16:38

chepner

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Why the first if statement conditional is ignored and the last else is executed?

2 Answers2