Sorting Python list by length of items' sub-property

Asked Oct 08 '19 at 08:16

Active Oct 08 '19 at 08:23

Viewed 193 times

I have a list called agents containing Agent objects. Each object has a solved property which is a list, for example:

Agent.solved = [300, 50, 100, 7]

The length of each list is different. I want to print results like this but I want the output ordered by the length of the solved property. How can I sort it that way?

for _id, obj in agents.items():
  print(obj, 'solved', len(obj), 'tickets')

asked Oct 08 '19 at 08:16

Elliott B

Does your code work? If not, could you post your attempt? – Corsaka Oct 08 '19 at 08:18
5

`for agent in sorted(agents, key=lambda x: len(x.solved))..` ? – han solo Oct 08 '19 at 08:18
2

I thought you said, `agents` was a `list` ? – han solo Oct 08 '19 at 08:19

Sorting Python list by length of items' sub-property

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