Regex finds pattern

Question

how can I find by using regular expression the "c start" pattern which is multiple times addressed. In other words, this should find only when this pattern is found more than once. Below is an example of an xml, which shows twice the "c start", so I would like to know what is the regex in order to find it?

  <c start="11111" end="1111111" />
  <c start="11111" end="222222222" />
</action>
<action
  src="abc"
  system="2222">
  <param
    name="trackID"
    value="1"
    valueType="data">
  </param>
  <param
    name="trackName"
    value="track"
    valueType="data">
  </param>
  <c start="11111" end="1111111" />
  <c start="11111" end="222222222" />

I may have the following xml which doesn't have more that once the pattern.

  <c start="11111" end="1111111" />
</action>
<action
  src="abc"
  system="2222">
  <param
    name="trackID"
    value="1"
    valueType="data">
  </param>
  <param
    name="trackName"
    value="track"
    valueType="data">
  </param>
  <c start="11111" end="1111111" />

Please update your question accordingly. Have you been through [How do I ask a good question?](https://stackoverflow.com/help/how-to-ask). What did you try so far? — Mike Doe, Oct 08 '19 at 11:12
I would advise you to use an XML-parser instead, see also https://stackoverflow.com/questions/1732348/regex-match-open-tags-except-xhtml-self-contained-tags/1732454#1732454 (also applies to XML) — SylarBenes, Oct 08 '19 at 11:33

score 0 · Accepted Answer · answered Oct 08 '19 at 11:29

0

Please, try this:

<c\s+start=\"(?<start>[^\"]+)\"\s+end=\"(?<end>[^\"]+)\"\s+\/>

This expression has two groups named as start and end to retrieve values from quotes.

But you can use <c\s+start=\"([^\"]+)\"\s+end=\"([^\"]+)\"\s+\/> if you don't need named groups.

You can check your regex here: https://regex101.com/

answered Oct 08 '19 at 11:29

Maksym

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if I need to embed it to a bash script, how do I have to write it? – user10573594 Oct 08 '19 at 13:06

Regex finds pattern

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