How to use the return of regex match into another regex

Question

text = "I have usd **12** only."
var amount = text.match(\(?:USD|usd)\s+.? 
\d+\.?[0-9]{1,2}\);

it returns

usd *12

I'm trying to grab the number only out of this return?

Is it possible to use "amount" again like this:

amount.match(\\d+\.?[0-9]{1,2}\);

You should search for 'Groups' in regex, they will let you do it in one run. — Poul Bak, Oct 09 '19 at 15:26
`if (m=text.match(/\busd\s+(\d+(?:\.\d+)?)/i)) { console.log(m[1]); }`? — Wiktor Stribiżew, Oct 09 '19 at 15:27

ruohola · Answer 1 · 2019-10-09T15:34:43.727

1

You don't need two regexes for this. This regex will do the job on its own:

(?:USD|usd)\s+.*?(\d+(?:\.\d{1,2})?)

It will capture the number in a capture group, so you only need one regex:

"I have usd **12** only."           // -> 12
"I have usd 12.00 only."            // -> 12.00
"I have usd **** 12.00 **** only."  // -> 12.0

edited Oct 09 '19 at 15:34

answered Oct 09 '19 at 15:27

ruohola

1 Answers1