How to pass a PHP variable to ajax jquery

Question

I want to pass a PHP variable to Jquery AJAX. How can I achieve this? I tried the below script.

$query_sess="select id from users where username='".$_SESSION['username']."'";
$result_sess = mysqli_query($con,$query_sess) or die('error');
$row_sess= mysqli_fetch_assoc($result_sess);
$userID = $row_sess['id'];

I need to pass this $userID to the ajax. My ajax script is as follows:

$(document).ready(function(){

    function load_unseen_notification(view = '')
    {
     $.ajax({
      url:"fetch_notification.php",
      method:"POST",
      data:{view:view, userID: <?php echo $userID; ?>},
      dataType:"json",
      success:function(data)
      {
       $('.dropdown-menunot').html(data.notification);
       if(data.unseen_notification > 0)
       {
        $('.count').html(data.unseen_notification);
       }
      }
     });
    }

So, you need to call your `load_unseen_notification(view = '', userId)` with `` from *.php . Js file cannot parse php code, that why you should call your functions with arguments — mcklayin, Oct 10 '19 at 17:44
Well, then the answer is, you can't (not the way you're trying to, anyway) — Patrick Q, Oct 10 '19 at 17:44
I understood. Thank you. Will need to check some other options.. — Sanju Menon, Oct 10 '19 at 17:45

score 0 · Accepted Answer · answered Oct 10 '19 at 17:47

The PHP script can put the user ID into a global variable, which could be accessed from the JavaScript.

$query_sess="select id from users where username='".$_SESSION['username']."'";
$result_sess = mysqli_query($con,$query_sess) or die('error');
$row_sess= mysqli_fetch_assoc($result_sess);
$userID = $row_sess['id'];
?>
<script>
var userID = <?php echo $userID; ?>;
</script>

Then in the AJAX call you can refer to that variable.

      data:{view:view, userID: userID},

How to pass a PHP variable to ajax jquery

1 Answers1