import java.util.Scanner;
public class Testing {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Enter a message");
String message = input.nextLine();
message = message.toLowerCase();
message = message.replaceAll("\\s+", "");
for(int i = 0; i < message.length(); i++) {
//i = the position
System.out.println(i);
//z = the character at position i
char z = message.charAt(i);
System.out.println(z);
}
}
}
This java takes a string and returns each character along with its respective index from the message. I want to make some python that does the same thing.
message = raw_input( "Enter a message ")
message = message.replace(" ", "")
message = message.lower()
print message
for i in message :
#i = each character in message
print i
#I want to print the position of character
#i in the message
print #????
I could use message.index(i) but when there are repeat letters it will only find the first.
How to find all occurrences of an element in a list?
This question was answered using indices, but that returns the values of all occurrences of that character. I only want one index at a time.
For example, if I input the message 'hello world' I want the output to be 0 h 1 e 2 l 3 l 4 0 etc. It was easy to do this with java because the for-loop creates the index first, then uses that index to find the character. The python code works a bit backwards, at least right now. First it finds every character in the message, but then I'm searching for that character in the message. Can I use a for-loop more similarly to the way I did in Java? is there a better way?
