Why does print(zip(A)), give output in the form , but expected output when doing set(zip(A))? Note that A is a list

Question

I do understand this is an object, but can you throw some insights on how it is able to map to different lists?

I do not understand your question. What did you expect `print(zip(*A))` to print? What do you mean "map to different lists"? for example: https://stackoverflow.com/questions/19777612/python-range-and-zip-object-type — juanpa.arrivillaga, Oct 22 '19 at 00:58

score 0 · Answer 1 · answered Oct 22 '19 at 01:03

In Python, the zip functions returns a custom iterator object that computes each tuple of items from the sequence it is given lazily. This object has no __repr__ method, so printing it produces the default <zip object at <address>>. The set constructor then evaluated the created iterator, creating a set of tuples. Sets do have a __repr__, so printing the set will produce the expected output.

Why does print(zip(*A)), give output in the form , but expected output when doing set(zip(*A))? Note that A is a list

1 Answers1

Why does print(zip(A)), give output in the form , but expected output when doing set(zip(A))? Note that A is a list