I have int numbers with values between 0-65535. I need to store each number as a byte array of 2 bytes length, whether the number could fit on 1 byte as well or not. Once the numbers are stored in byte arrays, I need to be able to convert them back to int. Right now I don't know how to store a number that is not between -32,768 and 32,767 on 2 bytes and be able to properly convert it back to its original int value.
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sasieightynine
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Possible duplicate of [Java - Convert int to Byte Array of 4 Bytes?](https://stackoverflow.com/questions/6374915/java-convert-int-to-byte-array-of-4-bytes) – Progman Nov 01 '19 at 14:07
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I need 2 bytes, not 4. – sasieightynine Nov 01 '19 at 14:09
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Look at using shift to access desired byte and AND to stripe off sign bits – NormR Nov 01 '19 at 14:11
2 Answers
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You can store values from 0-65535 in a char-value and convert a char to byte[] (with a length of 2) using the following method:
public static byte[] toBytes(char c) {
return ByteBuffer.allocate(Character.BYTES).putChar(c).array();
}
See here
EDIT:
Works backwards using ByteBuffer to:
public static char charFromBytes(byte[] bytes) {
return ByteBuffer.wrap(bytes).getChar();
}
Felix
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Storing the first byte as: (byte) (myIntNumber >> 8) and the second as (byte) myIntNumber seems working just fine for int -> byte array conversion, I'm still curious about how do I get back the int properly from a byte array.
sasieightynine
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You can just use my solution and cast from `int` to `char` and vice-versa – Felix Nov 01 '19 at 21:21