openURL not being called when I launch the app from Scheme Url (Swift project)

Question

When I open my application through myapp://param1=abc the open url function is not called.

I've added functions didFinishLaunchingWithOptions and willFinishLaunchingWithOptions to make it true, as the Apple documentation says, but it's still not called. The application opens perfectly, but not calling the function open url I can not get the param1

This is my AppDelegate file:

class AppDelegate: UIResponder, UIApplicationDelegate  {

    func application(_ application: UIApplication,
                     didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey : Any]? = nil) -> Bool {
        return true
    }

    func application(_ application: UIApplication, willFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey : Any]? = nil) -> Bool {
        return true
    }

    func application(_ application: UIApplication, open url: URL, options: [UIApplication.OpenURLOptionsKey : Any] = [:]) -> Bool {
        // Here doesn't come! :(
        return true
    }


    // MARK: UISceneSession Lifecycle


    func application(_ application: UIApplication, configurationForConnecting connectingSceneSession: UISceneSession, options: UIScene.ConnectionOptions) -> UISceneConfiguration {
        // Called when a new scene session is being created.
        // Use this method to select a configuration to create the new scene with.
        return UISceneConfiguration(name: "Default Configuration", sessionRole: connectingSceneSession.role)
    }

    func application(_ application: UIApplication, didDiscardSceneSessions sceneSessions: Set<UISceneSession>) {
        // Called when the user discards a scene session.
        // If any sessions were discarded while the application was not running, this will be called shortly after application:didFinishLaunchingWithOptions.
        // Use this method to release any resources that were specific to the discarded scenes, as they will not return.
    }
}

Any idea what might be going on?

Thanks!

You will have to check launchOptions dictionary in didFinishLaunchingWithOptions(). — Jitendra, Nov 07 '19 at 12:06
@Jitendra launchOption dictionary in didFinishLaunchingWithOptions() is nil. — Eric Gutiérrez Llopis, Nov 07 '19 at 12:11
Does this answer your question? [Method 'application:openURL:options:' is not called](https://stackoverflow.com/questions/58624786/method-applicationopenurloptions-is-not-called) — Hejazi, Dec 17 '19 at 11:36

PGDev · Answer 1 · 2019-11-07T15:14:51.927

4

The signature of openUrl method in AppDelegate is updated to,

func application(_ app: UIApplication, open url: URL, options: [UIApplication.OpenURLOptionsKey : Any] = [:]) -> Bool {
    return true
}

You need to add your urlScheme in the URL Types under Info tab in project settings, i.e.

For Swift-5 and iOS-13:

In SceneDelegate.swift file, you need to implement the below method to handle urlSchemes, i.e.

func scene(_ scene: UIScene, openURLContexts URLContexts: Set<UIOpenURLContext>) {
    print(URLContexts)
}

edited Nov 07 '19 at 15:14

answered Nov 07 '19 at 12:08

PGDev

23,751
6
34
88

I had already added my urlSchema. The URL opens the application well but does not call the function to get the parameters – Eric Gutiérrez Llopis Nov 07 '19 at 12:19
Have you tried putting the breakpoint there? Because it is working fine at my end. – PGDev Nov 07 '19 at 12:19
If it still doesn't work, try implementing the same in a brand new project and see if it works. – PGDev Nov 07 '19 at 12:20
I created a new project and all I did was add the openURL function and I added the url types and it doesn't work. – Eric Gutiérrez Llopis Nov 07 '19 at 12:33
Open myapp:// from safari and see if it is working. – PGDev Nov 07 '19 at 12:37
When open myapp:// from safari, the app opens but open url function not called – Eric Gutiérrez Llopis Nov 07 '19 at 12:40
Which iOS and Swift version are you using? – PGDev Nov 07 '19 at 12:44
ios13 and swift 5 – Eric Gutiérrez Llopis Nov 07 '19 at 12:46
Updated the answer for Swift-5 and iOS-13. – PGDev Nov 07 '19 at 15:15

score 1 · Answer 2 · answered Nov 13 '20 at 14:03

1

Since iOS 14 you can use deep links instead:

struct ShapifyApp: App {
    var body: some Scene {
        WindowGroup {
            ContentView()
                .onOpenURL { url in
                    //Whatever you need to do goes here
                }
        }
    }
}

answered Nov 13 '20 at 14:03

chikko

416
5
9

So many thanks to you that this is the only correct answer for me that resolved why my application method is not being called. Days wasted. – Peach Jul 16 '22 at 21:49

score 0 · Answer 3 · answered Nov 07 '19 at 12:16

0

application(_ application: UIApplication, open url will not call at the time of app launch. you need to access the launchOptions: [UIApplication.LaunchOptionsKey: Any] and your url with the help of [UIApplication.LaunchOptionsKey.url]

Here is the snippet that might help you

   func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {

        let url = launchOptions![UIApplication.LaunchOptionsKey.url]
        ...

        return true
    }

answered Nov 07 '19 at 12:16

Maulik Pandya

2,200
17
26

1

launchOptions is always nil – Eric Gutiérrez Llopis Nov 07 '19 at 12:24
1

any update on this? I see the same issue; open url handler doesn't get called at the time of app launch and also the launchOptions are nil. – ejps Jan 23 '20 at 19:36

score 0 · Answer 4 · answered Mar 29 '22 at 04:57

0

You can find the launch URL as follows:

 func scene(_ scene: UIScene, willConnectTo session: UISceneSession, options connectionOptions: UIScene.ConnectionOptions) {
  if let url = connectionOptions.urlContexts.first {
     ...
  }
}

answered Mar 29 '22 at 04:57

davidbaraff

181
1
6

openURL not being called when I launch the app from Scheme Url (Swift project)

4 Answers4