How to select custom filter by expression?

Question

How to do this in angularjs ?

I have field value and is_first_filter(where true or false). Where is_first_filter is true I want filtered field value by firstCustomFilter.

I can do this.

<p>field | is_first_filter ? firstCustomFilter : secondCustomFilter</p>

But it gives an error, so how can I select a filter by expression ?

Please describe what you want to accomblish and how what behavior you expect. To keep it short: Please describe "this" in your first sentence — lynxSven, Nov 13 '19 at 08:08

score 0 · Accepted Answer · answered Nov 13 '19 at 08:14

0

One option would be to pass arguments to angular filter as described here

Another option would be with tenary operator

{{ is_first_filter ? (field  | firstCustomFilter ) : (field | secondCustomFilter) }}

answered Nov 13 '19 at 08:14

Athanasios Kataras

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How to select custom filter by expression?

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