How to destructure an object without one key

Question

I have an object like obj = { test1: 'sth', test2: 'sth', label: 'sth' }.

And I would like to destructure this object {...obj} except label to get { test1: 'sth', test2: 'sth' }.

How to destructure the object without this key?

Should I create a new object or is there any way to do this simply in one line?

readability would suggest to simply copy the properties you want, it would be more clear from a reviewers stand point that's intended :) — Icepickle, Nov 17 '19 at 20:19
You can do the following: `const {label, ...exceptLabel} = obj;` — Chau Tran, Nov 17 '19 at 20:20

Zoidberg · Accepted Answer · 2019-11-17T23:51:47.187

6

Simple delete should do the trick.

delete obj.label;

EDIT: apparently my question did not do destructuring properly. Perhaps something like the following would work then.

({label, ...rest} = {test1: 'sth', test2: 'sth', label: 'sth' });
console.debug(rest);

Rest should contain only test1 and test2 properties/values.

edited Nov 17 '19 at 23:51

answered Nov 17 '19 at 20:19

Zoidberg

Based on the question, it seemed the person asking simply wanted to remove the single property from an object. Communication is key, I would ask why they want to destructure in the first place when something simpler would do. – Zoidberg Nov 17 '19 at 23:48

1 Answers1