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var x = 1;
function fn() {
 console.log(x);
}
function show(f){
 var x = 2;
 f();
}
show(fn);

fn() function should have access to its outer execution context show(), which x is define as 2.

Bergi
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Ethan.Wang
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    JavaScript has lexical scope, not dynamic scope. It considers the source code location, not the call stack. – Bergi Nov 19 '19 at 00:36
  • Btw, your example is unnecessarily complicated. You could just have called `fn()` from within `show`, no need to pass it as an argument `f`. – Bergi Nov 19 '19 at 00:38

1 Answers1

0

No. f is bound with the context as it was when f was defined, that is, when x = 1. If you want x = 2, you need to define fn inside of the show function.

Travis Webb
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