How do I print an init() inside of a function?

Question

Whenever I'm trying to print the code below I get <__main__.Initial object at 0x106071ee0>:

# INITILIZATION
class Initial:
    def __init__(self, arg1, arg2, arg3, arg4, arg5):
        self.definition = arg1
        self.other = arg2
        self.present = arg3
        self.imperfect = arg4
        self.perfect = arg5


# DEFINITIONS

def salve():
    dictator = Initial("hello\n" ,"Salvete = hello (plural)\n" , None , None, None)
    print(dictator)
salve()

How do I print desired arguments using standard print function?

Yes it does, but now I can't delete my question since someone else wrote down an answer — Sergio Ley-Languren, Nov 23 '19 at 19:32
Deleting isn't necessary, and the comment that that user posted was auto-generated by the site btw. — Carcigenicate, Nov 23 '19 at 19:39

score 1 · Accepted Answer · answered Nov 23 '19 at 19:30

1

Each class allows you to override __str__ method you would do something like this

class Initial:
    def __init__(self, arg1, arg2, arg3, arg4, arg5):
        ...

    def __str__(self):
        print(f"definition={self.definition}, {self.other}")

answered Nov 23 '19 at 19:30

sultan

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How do I print an __init__() inside of a function?

1 Answers1

How do I print an init() inside of a function?