Python Function that returns None

Question

I don't understand, why is foo() returning None?

def foo(a,b):
    if a+b == 12:
        return True
print(foo(7,5)) # Works fine
print(foo(1,3)) # prints None

python functions always return something. When you don't explicitly return a value, they will return a None implicitly. — Paritosh Singh, Nov 24 '19 at 09:11

Some Guy · Accepted Answer · 2020-06-23T14:31:47.463

-4

You should return another bool if a+b is not 12

def foo(a,b):
    if a+b == 12:
        return True
    else:
        return False
answer1 = foo(1,3)
answer2 = foo(7,5)
if answer1:
    print "1 + 3 = 12"
if answer2:
    print "7 + 5 = 12"

foo() will return True if a+b == 12, if not should return False

edited Jun 23 '20 at 14:31

answered Nov 24 '19 at 09:09

Some Guy

378
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6

6

Please don’t make a boolean test to decide which boolean to return. Directly return the test results. – MisterMiyagi Nov 24 '19 at 09:11
2

`1plus3is12` and `7plus5is12` are not valid variable names. – khelwood Nov 24 '19 at 09:45

Python Function that returns None

1 Answers1