I need to filter row by a bash variable.
var=$(cat $1 | awk -F"\t" ' $1 == "foo1" { print $0 }')
echo $var
I'm trying this to replace the string "foo1" to a variable
column2=$(echo "foo1")
echo $column2
var=$(cat $1 | awk -v pres=$column2 -F"\t" ' $1 == $pres { print $0 }')
echo $var
In the parameter $1 i pass a file.txt that have the next text
foo2    AAAA    561214
foo3    AAAA    3
foo4    AAAA    10470670
foo5    AAAA    443507
foo1    AAAA    12473709
foo6    AAAA    1599707
foo8    AAAA    382820
foo7    BBBB    100000000000000
foo1    AAAA    12473709
foo1    AAAA    12473709
foo1    AAAA    12473709
foo1    AAAA    12473709
foo1    AAAA    12473709
foo1    AAAA    12473709
foo1    AAAA    12473709
I need to do this with a variable, because i need to loop for each distinct value of the first column.
EDIT
#My question is different than bash-How do i use shell variable in a awk script because i need to do a conditional to filter rows of a table in a file. I can do that is posted in that link, but i don't know how to combine to do
var=$(cat $1 | awk -F"\t" ' $1 == "foo1" { print $0 }')
that is working but when i tried to insert the variable stop working.
 
     
    