I have been experimenting with this code:
    <html>
<head>
    <title>Test</title>
    <h3>Test</h3>
</head>
<body>
    <?php
        $name = $_POST["name"];
        $age = $_POST["age"];
        $con = new mysqli("localhost","root","","server");
        if ($con->connect_error) {
            die("Connection failed: " . $con->connect_error);
        }
        $sql = "SELECT * FROM `joinedplayers`";
        $result = $con->query($sql);
        if ($result->num_rows > 0) {
        // output data of each row
            while($row = $result->fetch_assoc()) {
                echo $row["num"]. " - Name: " . $row["name"]. " - Age: " . $row["age"]. " <button type = 'button'> Get Info </button>  <br><br>";
            }
        } else {
            echo "0 results";
        }
        $con->close();
    ?>
</body>
</html>
Btw: I'm using XAMPP and phpMyAdmin
For some reason, I can't send requests to the script. I have a table that holds 3 values: the current number (first-person = 1, second-person = 2 and so on...) the name (varchar) and an age value which holds an int. If I run this, without the two lines with $_POST, it works fine and lists all the objects in the table as I want it too. Also, the MySQLI is connecting to the localhost just fine. Is there any way to get the values sent as a post and add them to the database?
Also, here is the code I used inside of Fiddler 4: name=test&age=5
 
     
    