This might be a really stupid question but is it possible to keep a local empty list updated in this instance:
def voeg_vriendschap_toe(sn, naam_persoon1, naam_persoon2):
    relaties = []
    count_variabel = 0
    aanwezig_persoon1 = False
    aanwezig_persoon2 = False
    uitvoeren = True
    for i in relaties:
        if((i[0] == naam_persoon1) and (i[1] == naam_persoon2)):
            uitvoeren = False
    while ((len(sn) > count_variabel) and ((aanwezig_persoon1 == False) or (aanwezig_persoon2 == False)) and (uitvoeren == True)):
        if (sn[count_variabel] == naam_persoon1):
            aanwezig_persoon1 = True
        if (sn[count_variabel] == naam_persoon2):
            aanwezig_persoon2 = True
        count_variabel += 1
    if ((aanwezig_persoon1 == True) and (aanwezig_persoon2 == True)):
        sn.append([naam_persoon1, naam_persoon2])
        sn.append([naam_persoon2, naam_persoon1])
        relaties.append([naam_persoon1, naam_persoon2])
        relaties.append([naam_persoon2, naam_persoon1])
        return sn
    else:
        return sn
I want relaties to be updated after the appends and not be an empty list again when the function is called multiple times.
So in case voeg_vriendschap_toe() is called once, and relaties is updated to [[1,2], [2,1]]. However if it's called again it becomes an empty list again rather than keeping its value. Is it possible to have it keep its value without using a global variable?