Simulate jQuery.ajax request in PHP

Question

I have to simulate AJAX request in PHP, exactly as is in jQuery. My current code is here:

Original AJAX call (mustn't be modified)

$.ajax({
    type: "POST",
    url: "/someFile.php",
    data: data,
    success: function(response) {
        some_code_here;
    },
    error: function() {
        some_code_here;
    }
});

Current PHP code - trying to simulate JS's code behaviour above

function _misc_test() {

    $data = json_decode("xxx"); // The "xxx" is placeholder for the same string, as is in data var in JS above

    $ajaxResponse = _make_post_request('/someFile.php', $data);
    print_r($ajaxResponse);
}

function _make_post_request($url, $data) {
    $ch = curl_init($url);

    curl_setopt($ch, CURLOPT_POST, TRUE);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

    $response = curl_exec($ch);
    curl_close($ch);
    return $response;
}

And unfortunatelly, the PHP code doesn't seems to generate exactly the same packets like JS code - that's what I need. Can anyone give me a hand please?

EDIT: maybe it's important, that data variable in JS holds complex JS object like this one:

{"options":{"userIP":"89.102.122.16","playerType":"flash","playlistItems":[{"Type":"Archive","Format":"MP4_Web","Identifier":"209 452 80139\/0042","Title":"Nezn\u00e1m\u00ed hrdinov\u00e9","Region":"","SubtitlesUrl":"http:\/\/img2.ceskatelevize.cz\/ivysilani\/subtitles\/209\/209452801390042\/subtitles-1.txt","Indexes":null,"Gemius":{"Param":[{"Name":"materialIdentifier","Value":"209 452 80139\/0042"},{"Name":"testParam","Value":"testValue"}]}}],"previewImageURL":null}}

Do you have a question too or do you just want to share your experience? If the latter, then SO is not the right place for this. — Felix Kling, May 07 '11 at 00:47
I'm sorry, I've posted just a concept by mistake. Now it is edited. — tomasbedrich, May 07 '11 at 00:53
*doesn't seems to generate exactly the same packets* what does that mean? — Felix Kling, May 07 '11 at 01:18

score 0 · Accepted Answer · edited May 23 '17 at 11:47

in js : data: $('form').serialize();

in php : How to post data in PHP using file_get_contents?

$jsonstr = '{"options":{"userIP":"89.102.122.16","playerType":"flash","playlistItems":[{"Type":"Archive","Format":"MP4_Web","Identifier":"209 452 80139\/0042","Title":"Nezn\u00e1m\u00ed hrdinov\u00e9","Region":"","SubtitlesUrl":"http:\/\/img2.ceskatelevize.cz\/ivysilani\/subtitles\/209\/209452801390042\/subtitles-1.txt","Indexes":null,"Gemius":{"Param":[{"Name":"materialIdentifier","Value":"209 452 80139\/0042"},{"Name":"testParam","Value":"testValue"}]}}],"previewImageURL":null}}';

print_r(
    $data = json_decode($jsonstr ,true)
);

$data_url = http_build_query ($data);
$data_url = str_replace("amp;","",$data_url); //fix for &amp; to &


$data_len = strlen ($data_url);
$url      = 'http://domain.com/returnPost.php';

$result =  file_get_contents ($url, false, 
    stream_context_create (
        array ('http'=>
            array ('method'=>'POST'
            , 'header'=>"Connection: close\r\nContent-Length: $data_len\r\n"
            , 'content'=>$data_url
            ))
        )
    );

print_r(
  $result
);

in returnPost.php

print_r($_POST);

Ok, thanks - I'll try and give a report (accept your solution) if it will work — tomasbedrich, May 07 '11 at 01:03
I'm, sorry, but I got the same error. Maybe the contents of JS's `data` variable is important - so I edited the original post. Please take a look at it again. — tomasbedrich, May 07 '11 at 11:41
$data_url = str_replace("amp;","",$data_url); fix for & to & — misima, May 12 '11 at 12:00

Simulate jQuery.ajax request in PHP

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