The current expression validates a web address (HTTP), how do I change it so that an empty string also matches?
(http|https):\/\/[\w\-_]+(\.[\w\-_]+)+([\w\-\.,@?^=%&:/~\+#]*[\w\-\@?^=%&/~\+#])?
The current expression validates a web address (HTTP), how do I change it so that an empty string also matches?
(http|https):\/\/[\w\-_]+(\.[\w\-_]+)+([\w\-\.,@?^=%&:/~\+#]*[\w\-\@?^=%&/~\+#])?
 
    
     
    
    If you want to modify the expression to match either an entirely empty string or a full URL, you will need to use the anchor metacharacters ^ and $ (which match the beginning and end of a line respectively).
^(|https?:\/\/[\w\-_]+(\.[\w\-_]+)+([\w\-\.,@?^=%&:/~\+#]*[\w\-\@?^=%&/~\+#])?)$
As dirkgently pointed out, you can simplify your match for the protocol a little, so I've included that for you too.
Though, if you are using this expression from within a program or script, it may be simpler for you to use the languages own means of checking if the input is empty.
// in no particular language...
if input.length > 0 then
    if input matches <regex> then
        input is a URL
    else
        input is invalid
else
    input is empty
 
    
    Put the whole expression in parenthesis and mark it as optional (“?” quantifier, no or one repetition)
((http|https):\/\/[\w\-_]+(\.[\w\-_]+)+([\w\-\.,@?^=%&:/~\+#]*[\w\-\@?^=%&/~\+#])?)?
 
    
     
    
    Use expression markers ^$ around your expression and add |^$ to the end. This way you're using the | or operator with two expressions showing that you have two different match cases.
^(https?:\/\/[\w\-_]+(\.[\w\-_]+)+([\w\-\.,@?^=%&:/~\+#]*[\w\-\@?^=%&/~\+#])?)$|^$
The key here is that |^$ means "or match blank".
Also, that expression with only work in javascript if you use a template string.
 
    
    Expr? where Expr is your URL matcher. Just like I would for http and https: https?. The ? is a known as a Quantifier -- you can look it up. From Wikipedia:
? The question mark indicates there is zero or one of the preceding element.
