I am new in regular expression. I want to remove a uppercase letter if it has lowercase before and after it. If the input is "I wilYl go theXre" then the output should be "I will go there". How can I get it?
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Ṃųỻịgǻňạcểơửṩ
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Sajib
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Regex for uppercase before lowercase is [a-z][A-Z] – Ṃųỻịgǻňạcểơửṩ Dec 09 '19 at 17:53
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1"I will go thereX" returns what? – Dani Mesejo Dec 09 '19 at 17:53
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`I wilYl go theXre` is input, `I will go there` is output. The `Y` and `X` are removed because it matches `[a-z][A-Z]` – Ṃųỻịgǻňạcểơửṩ Dec 09 '19 at 17:54
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How can I write it in python? – Sajib Dec 09 '19 at 17:56
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What does it means is ok? Do you want to remove it too? – Dani Mesejo Dec 09 '19 at 17:56
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No only the uppercase which has lowercase before and after. Last uppercase is not necessary. – Sajib Dec 09 '19 at 18:04
1 Answers
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You can use a lookaround:
import re
s='I wilYl go theXre'
print(re.sub(r'(?<=[a-z])([A-Z])(?=[a-z])','',s))
# ^ lookbehind ^lookahead
Prints:
I will go there
dawg
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