How to put android WebView in AlertDialog?

Question

I'm trying to put webview in alertdialog, I'm using code I found somewhere on the stack but for some reason, it doesn't work.

Here's an example of my code:

holder.textView4.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                AlertDialog.Builder alert = new AlertDialog.Builder(context);
                alert.setTitle("Google:");

                View view = LayoutInflater.from(context).inflate(R.layout.webLayout, null);

                WebView wv = view.findViewById(R.id.webview);

                wv.loadUrl(link);
                wv.setWebViewClient(new WebViewClient() {
                    @Override
                    public boolean shouldOverrideUrlLoading(WebView v, String url) {
                        v.loadUrl(url);
                        return true;
                    }
                });

                alert.setView(view);
                alert.setNegativeButton("Close", new DialogInterface.OnClickListener() {
                    @Override
                    public void onClick(DialogInterface dialog, int id) {
                        dialog.dismiss();
                    }
                });
                alert.create().show();
            }
        });

webLayout.xml:

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical" android:layout_width="match_parent"
    android:layout_height="match_parent">

    <WebView
        android:id="@+id/webview"
        android:layout_width="match_parent"
        android:layout_height="match_parent">
    </WebView>

</LinearLayout>

After click on button only empty dialog shows:

`for some reason, it doesn't work` you have to tell us what you mean with this. _what_ doesn't work — a_local_nobody, Dec 23 '19 at 16:08
Does this answer your question? [android: webview inside dialog or popup](https://stackoverflow.com/questions/9172805/android-webview-inside-dialog-or-popup) — Sazzad Hissain Khan, Dec 23 '19 at 17:13

daniel.jbatiz · Accepted Answer · 2019-12-23T21:25:25.503

2

Have you added the INTERNET Permission to the Manifest? <uses-permission android:name="android.permission.INTERNET"/>

You got to create an xml layout fisrt, and put the webview in the layout

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical" android:layout_width="match_parent"
    android:layout_height="match_parent">

    <!--Configure the webview as you want-->
    <WebView
        android:id="+id/webview"
        android:layout_width="match_parent"
        android:layout_height="match_parent">
    </WebView>

</LinearLayout>

create a view object instead a webview

View view = LayoutInflater.from(context).inflate(R.layout.layout_with_webview , null)

Now to crete a webview object use WebView webView = view.findViewById(R.id.webview) Pass that view to alert.setView(view)

And the most important alertDialogBuilder.show()

edited Dec 23 '19 at 21:25

answered Dec 23 '19 at 16:01

daniel.jbatiz

437
4
18

show() automatically calls create(). You don't need to create yourself – Tim Dec 23 '19 at 16:22
Are you sure about that ? – daniel.jbatiz Dec 23 '19 at 16:24
Yes, I'd also say, that create() is not necessary. – the_dani Dec 23 '19 at 16:25
@daniel.jbatiz updated first post, still just empty dialog shows – Niklaus Dec 23 '19 at 16:38
have you added the internet permission – daniel.jbatiz Dec 23 '19 at 16:40
wv.loadUrl("https://www.google.com") works correctly on my device. So check the url you're reciving and check that webclient – daniel.jbatiz Dec 23 '19 at 17:01
to discard a problem on the webclient just try wb.loadUrl("https://www.google.com) without wv.setWebClient() code – daniel.jbatiz Dec 23 '19 at 17:03
Still nothing, It literally looks unsolvable – Niklaus Dec 23 '19 at 17:08
common, you know how to debug ok ? , so put a breakpoint at wv.loadUrl(link) and see what is inside the variable – daniel.jbatiz Dec 23 '19 at 17:11
put another at v.loadUrl(url) and check url and v – daniel.jbatiz Dec 23 '19 at 17:20
@daniel.jbatiz see picture in fisrt post – Niklaus Dec 23 '19 at 17:27
It works now with google and facebook, but it dont work with my link – Niklaus Dec 23 '19 at 17:37
whats your link ? – daniel.jbatiz Dec 23 '19 at 17:38
add to the manifest android:usesCleartextTraffic="true" inside – daniel.jbatiz Dec 23 '19 at 17:40

Sazzad Hissain Khan · Answer 2 · 2019-12-24T05:29:14.293

0

Just replace

alert.create().show();

into

alert.show();

Update:

Please use https:// in your url rather http:// or blank. Also you need to add clear text support if you really want to use non secure url. Please see how to configure here (https://stackoverflow.com/a/50834600/1084174)

edited Dec 24 '19 at 05:29

answered Dec 23 '19 at 17:17

Sazzad Hissain Khan

37,929
33
189
256

It’s true that’s not necesary the create() ‘cause show() calls create() , but the error seems to be at the specific url he is trying to load (google.com is just for check if works – daniel.jbatiz Dec 23 '19 at 21:24
In that case the issues seems for the firewall. May be posters url is not permitted. He needs to check with other urls. @daniel – Sazzad Hissain Khan Dec 24 '19 at 03:38
He tried with google and facebook and works correctly – daniel.jbatiz Dec 24 '19 at 04:46

score 0 · Answer 3 · answered Dec 24 '19 at 06:25

0

Try this in AndroidManifest.xml

  <application
        android:name="com.****.***"
        ****************
        ************
        *******
        .
        .
        .
        android:usesCleartextTraffic="true"
        >

answered Dec 24 '19 at 06:25

Ak23

342
1
5
17

How to put android WebView in AlertDialog?

3 Answers3