How can I execute a try statement again when KeyError is thrown in Python?

Question

In this code, I want to execute try again when an exception occurs.

What are the various ways?

type_input = 0

print("Welcome to the fantastic Mud Shopping Mall, MADMUDSHOP!!")
print("(Select your member type.)")
print("1. Administrator \t 2. User ")

command = {
    1 : print_admin_home,
    2 : print_user_home
}

type_input = int(input())


try:
    command[type_input]()
except KeyError:
    print("You mistyped it!")

Thank you for kindly answer! I forgot that there is an "else" in the try syntax. — Nemomong, Dec 30 '19 at 17:42
You may now think about accepting an answer or comment one to get details ;) to reward those who spent time for you ;) — azro, Jan 03 '20 at 15:23

score 1 · Accepted Answer · answered Dec 30 '19 at 17:39

1

You put it in a while loop, that will loop forever :

command = {1: print_admin_home, 2: print_user_home}
print("Welcome to the fantastic Mud Shopping Mall, MADMUDSHOP!!")
while True:
    print("Select your member type:\n1. Administrator \n2. User")
    type_input = int(input())
    try:
        command[type_input]()
    except KeyError:
        print("You mistyped it!")

answered Dec 30 '19 at 17:39

azro

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Thank you for the specific answer! Has been a great help to me! – Nemomong Dec 30 '19 at 17:45

How can I execute a try statement again when KeyError is thrown in Python?

1 Answers1